Which statement best describes the area of Triangle ABC shown below?
It is twice the area of a square of side length 4 units. It is one-half the area of a square of side length 4 units. It is twice the area of a rectangle with sides 4 units × 3 units. It is one-half the area of a rectangle with sides 4 units × 3 units.
It is one-half the area of a rectangle with sides 4 units × 3 units. Just plot the points, and you can see that the base is 4, and the height is 3. So using the triangle area formula, we have 4 * 3 * 1/2 = 6. Go through each of these equations and you can see that the last one is the only one that satisfies this triangle.
Hope this helps!
The statement that would best discribe the area of Triangle ABC is:
It is one-half the area of a rectangle with sides 4 units × 3 units.
Heres an Explination of why:
The formula of area of a triangle: \(\frac{1}{2} * base * height\)
Base of triangle = 4 units.
Height of triangle = 3 units
\(\frac{1}{2} * 4 * 3\) =
\(\frac{12}{2} = 6 units^2\)
So if you used the statment "It is one-half the area of a rectangle with sides 4 units × 3 units." It will look like:
Area of a rectangle: Length * Width
= 4 * 3
12 \(units^2\)
Area of the triangle: 6 square units
Area of the rectangle: 12 square units
\(6=\frac{1}{2}* 12\)
6 = 6
Hope this helps ;P