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Which statement best describes the area of Triangle ABC shown below?

A triangle ABC is shown on a grid. The vertex A is on ordered pair 4 and 5, vertex B is on ordered pair 6 and 2, and the vertex C is on ordered pair 2 and 2. It is twice the area of a square of side length 4 units. It is one-half the area of a square of side length 4 units. It is twice the area of a rectangle with sides 4 units × 3 units. It is one-half the area of a rectangle with sides 4 units × 3 units.

 Mar 14, 2019
 #1
avatar+235 
+2

It is one-half the area of a rectangle with sides 4 units × 3 units. Just plot the points, and you can see that the base is 4, and the height is 3. So using the triangle area formula, we have 4 * 3 * 1/2 = 6. Go through each of these equations and you can see that the last one is the only one that satisfies this triangle.

 

Hope this helps!

 Mar 14, 2019
 #2
avatar+1014 
-4

Here are my answers just to know...

Nickolas  Mar 14, 2019
 #3
avatar+1014 
-4

It is twice the area of a square of side length 4 units.

It is one-half the area of a square of side length 4 units.

It is twice the area of a rectangle with sides 4 units × 3 units.

It is one-half the area of a rectangle with sides 4 units × 3 units.

Nickolas  Mar 14, 2019
 #5
avatar+235 
+2

It is one-half the area of a rectangle with sides 4 units × 3 units.

LagTho  Mar 14, 2019
 #4
avatar+219 
-4

The statement that would best discribe the area of Triangle ABC is:

It is one-half the area of a rectangle with sides 4 units × 3 units.

 

Heres an Explination of why:

The formula of area of a triangle: \(\frac{1}{2} * base * height\)

Base of triangle = 4 units.

Height of triangle = 3 units

 

\(\frac{1}{2} * 4 * 3\) = 

\(\frac{12}{2} = 6 units^2\)

 

So if you used the statment "It is one-half the area of a rectangle with sides 4 units × 3 units." It will look like:

 

Area of a rectangle: Length * Width

= 4 * 3

12 \(units^2\)

Area of the triangle: 6 square units

Area of the rectangle: 12 square units

\(6=\frac{1}{2}* 12\)

6 = 6

 

Hope this helps ;P

 Mar 14, 2019
 #6
avatar+1014 
-5

Thankyou to 

True words from 

~Joe Greaser 

 

Lol kidding 

Nickolas  Mar 14, 2019
 #7
avatar+235 
+2

Very nice, much neater than mine.

LagTho  Mar 14, 2019
 #8
avatar+1014 
-5

You did still really well...

Nickolas  Mar 14, 2019
 #9
avatar+219 
-5

XD No problem, LagTho did still do great ;P

EmeraldWonder  Mar 14, 2019

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