Which statement best describes the area of Triangle ABC shown below?

It is twice the area of a square of side length 4 units. It is one-half the area of a square of side length 4 units. It is twice the area of a rectangle with sides 4 units × 3 units. It is one-half the area of a rectangle with sides 4 units × 3 units.

Nickolas Mar 14, 2019

#1**+2 **

It is one-half the area of a rectangle with sides 4 units × 3 units. Just plot the points, and you can see that the base is 4, and the height is 3. So using the triangle area formula, we have 4 * 3 * 1/2 = 6. Go through each of these equations and you can see that the last one is the only one that satisfies this triangle.

Hope this helps!

LagTho Mar 14, 2019

#4**+1 **

The statement that would best discribe the area of Triangle ABC is:

It is one-half the area of a rectangle with sides 4 units × 3 units.

Heres an Explination of why:

The formula of area of a triangle: \(\frac{1}{2} * base * height\)

Base of triangle = 4 units.

Height of triangle = 3 units

\(\frac{1}{2} * 4 * 3\) =

\(\frac{12}{2} = 6 units^2\)

So if you used the statment "It is one-half the area of a rectangle with sides 4 units × 3 units." It will look like:

Area of a rectangle: Length * Width

= 4 * 3

12 \(units^2\)

Area of the triangle: 6 square units

Area of the rectangle: 12 square units

\(6=\frac{1}{2}* 12\)

6 = 6

Hope this helps ;P

EmeraldWonder Mar 14, 2019