n aeroplane is flying horizontally at a height 3150 mt. above a horizontal plane ground. At a particular instant, it passes another aeroplane vertically below it. At this instant, the angles of elevation of the planes from a point on the ground are 30 degrees and 60 degrees. Find the distance between the two planes at that instant.
+36916 Higher airplane tan 60 = opp/adj = 3150/adj
Lower airplane tan 30 = (3150-d)/adj Solve this system of equations for d tan 30 = .5774 tan 60 = 1.732
3150/1.732 = adj (from first eq)
sub into second equation
.5774 = (3150-d)/ (3150/1.732)
1050.12 = 3150-d
d= 2099.8 =~2100 m
