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n aeroplane is flying horizontally at a height 3150 mt. above a horizontal plane ground. At a particular instant, it passes another aeroplane vertically below it. At this instant, the angles of elevation of the planes from a point on the ground are 30 degrees and 60 degrees. Find the distance between the two planes at that instant.

 Jan 9, 2020
 #1
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Higher airplane      tan 60 = opp/adj = 3150/adj

Lower airplane       tan 30 = (3150-d)/adj                     Solve this system of equations for d   tan 30 = .5774   tan 60 = 1.732

 

3150/1.732 = adj (from first eq)

sub into second equation

 

.5774 = (3150-d)/ (3150/1.732)

1050.12 = 3150-d

d= 2099.8 =~2100 m   

 
 Jan 9, 2020

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