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A model rocket is launched directly upward at a speed of 50 meters per second from a height of 8 meters. The function f(t)=−4.9t2+50t+8, models the relationship between the height of the rocket at different times, t, in seconds. When, in seconds after launch, will the rocket hit the ground? Round to two decimal places.

 Feb 17, 2020
 #1
avatar+109740 
+1

We just need to solve this

 

-4.9t^2  + 50t  + 8   =   0

 

Using the  quadratic formula   we have

 

 

-50  ±√  [ 50^2 - 4 * (-4.9) (8) ]

____________________________   =  

          2 (-4.9)

 

 

-50  + 51.54

___________  =    negative  result

    -9.8

 

-50 - 51.54

__________  ≈   10.36 sec 

    -9.8  

 

 

 

cool cool cool

 Feb 17, 2020

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