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It’s takes 3/5 yard of ribbon to make a bow. How many bows could you make with 7 1/2 yards of ribbon?

 Jan 30, 2020
 #1
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We know that there are \(\frac{15}{2}\) yards of ribbon. So, to find the amount of bows we can divide.

 

Thus, \(\frac{15}{2} \div \frac{3}{5}\) will become \(\frac{15}{2} \cdot \frac{5}{3} \to \frac{5}{2} \cdot 5 \to \frac{25}{2} \to \boxed{12.5}\) laugh

 Jan 30, 2020
 #2
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Hi there...

 

Here is an alternative solution to the problem.

 

The numbers in the problem are "((3)/(5))" and "7 ((1)/(2))".

The fraction "((3)/(5))" is ok as is.
The fraction "7 ((1)/(2))" equals "((15)/(2))".

 

It's very easy to tell that the LCD is 10.
And thus...

((3)/(5))=((10)/((3)/(5)))=((6)/(10)) per Bow.

...and...

((15)/(2))=((10)/((15)/(2)))=((75)/(10)) Ribbon in total.

 

In turn...

(((75)/(10))/((6)/(10)))=((75)/(((10)*(6))/(10)))=((75)/(6))

...and...

(((75)/(6))/(3))=((25)/(2))
Finally...
((25)/(2))=(12.5) Bows in total.

I hope that made sense?


Kind regards

BizzyX



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 Jan 30, 2020
 #3
avatar+78 
0

-----

 

 

Hi there...

 

Here is an alternative solution to the problem.

 

The numbers in the problem are "(3/5)" and "7 and (1/2)".

The fraction "(3/5)" is ok as is.
The fraction "7 and (1/2)" equals "(15/2)".

 

It's very easy to tell that the LCD is 10.
And thus...

(3/5)=(10/(3/5))=(6/10) per Bow.

...and...

(15/2)=(10/(15/2))=(75/10) Ribbon in total.

 

In turn...

((75/10)/(6/10))=(75/((10*6)/10))=(75/6)

...and...

((75/6)/3)=(25/2)
Finally...
(25/2)=12.5 Bows in total.

I hope that made sense?


Kind regards

BizzyX



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 Jan 30, 2020
edited by BizzyX  Feb 6, 2020

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