It’s takes 3/5 yard of ribbon to make a bow. How many bows could you make with 7 1/2 yards of ribbon?
+304 We know that there are \(\frac{15}{2}\) yards of ribbon. So, to find the amount of bows we can divide.
Thus, \(\frac{15}{2} \div \frac{3}{5}\) will become \(\frac{15}{2} \cdot \frac{5}{3} \to \frac{5}{2} \cdot 5 \to \frac{25}{2} \to \boxed{12.5}\) 
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Hi there...
Here is an alternative solution to the problem.
The numbers in the problem are "((3)/(5))" and "7 ((1)/(2))".
The fraction "((3)/(5))" is ok as is.
The fraction "7 ((1)/(2))" equals "((15)/(2))".
It's very easy to tell that the LCD is 10.
And thus...
((3)/(5))=((10)/((3)/(5)))=((6)/(10)) per Bow.
...and...
((15)/(2))=((10)/((15)/(2)))=((75)/(10)) Ribbon in total.
In turn...
(((75)/(10))/((6)/(10)))=((75)/(((10)*(6))/(10)))=((75)/(6))
...and...
(((75)/(6))/(3))=((25)/(2))
Finally...
((25)/(2))=(12.5) Bows in total.
I hope that made sense?
Kind regards
BizzyX
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+87 -----
Hi there...
Here is an alternative solution to the problem.
The numbers in the problem are "(3/5)" and "7 and (1/2)".
The fraction "(3/5)" is ok as is.
The fraction "7 and (1/2)" equals "(15/2)".
It's very easy to tell that the LCD is 10.
And thus...
(3/5)=(10/(3/5))=(6/10) per Bow.
...and...
(15/2)=(10/(15/2))=(75/10) Ribbon in total.
In turn...
((75/10)/(6/10))=(75/((10*6)/10))=(75/6)
...and...
((75/6)/3)=(25/2)
Finally...
(25/2)=12.5 Bows in total.
I hope that made sense?
Kind regards
BizzyX
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