It’s takes 3/5 yard of ribbon to make a bow. How many bows could you make with 7 1/2 yards of ribbon?

Guest Jan 30, 2020

#1**0 **

We know that there are \(\frac{15}{2}\) yards of ribbon. So, to find the amount of bows we can divide.

Thus, \(\frac{15}{2} \div \frac{3}{5}\) will become \(\frac{15}{2} \cdot \frac{5}{3} \to \frac{5}{2} \cdot 5 \to \frac{25}{2} \to \boxed{12.5}\)

DragonLord Jan 30, 2020

#2**0 **

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Hi there...

Here is an alternative solution to the problem.

The numbers in the problem are "((3)/(5))" and "7 ((1)/(2))".

The fraction "((3)/(5))" is ok as is.

The fraction "7 ((1)/(2))" equals "((15)/(2))".

It's very easy to tell that the LCD is 10.

And thus...

((3)/(5))=((10)/((3)/(5)))=((6)/(10)) per Bow.

...and...

((15)/(2))=((10)/((15)/(2)))=((75)/(10)) Ribbon in total.

In turn...

(((75)/(10))/((6)/(10)))=((75)/(((10)*(6))/(10)))=((75)/(6))

...and...

(((75)/(6))/(3))=((25)/(2))

Finally...

((25)/(2))=(12.5) Bows in total.

I hope that made sense?

Kind regards

BizzyX

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Guest Jan 30, 2020

#3**0 **

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Hi there...

Here is an alternative solution to the problem.

The numbers in the problem are "(3/5)" and "7 and (1/2)".

The fraction "(3/5)" is ok as is.

The fraction "7 and (1/2)" equals "(15/2)".

It's very easy to tell that the LCD is 10.

And thus...

(3/5)=(10/(3/5))=(6/10) per Bow.

...and...

(15/2)=(10/(15/2))=(75/10) Ribbon in total.

In turn...

((75/10)/(6/10))=(75/((10*6)/10))=(75/6)

...and...

((75/6)/3)=(25/2)

Finally...

(25/2)=12.5 Bows in total.

I hope that made sense?

Kind regards

BizzyX

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BizzyX Jan 30, 2020