A quadratic function has a vertex point of (3,1) and passes through the point (6,-8).Which equation represents the quadratic equation?
A y=- x^2 + 6x-8
B y=x^2 - 6x +10
C y=- x^2 - 6x-8
D y=- x^2 + 6x -10
+128473 We have that
( y - k) = a( x - h)^2 where (x, y) is a point on the graph and (h, k) is the vertex.....solving for "a" we have
(-8 - 1) = a ( 6 - 3)^2
(-9) = a (3)^2
-9 = 9a
a = -1
So we have this
y = -1 ( x - 3)^2 + 1 expand and simplify
y = - (x^2 - 6x + 9) + 1
y = -x^2 + 6x - 9 + 1
y = -x^2 + 6x - 8
Here's the graph : https://www.desmos.com/calculator/403szzeeqc
