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Line 1l represents the graph of 3x+4y = -14. Line l2 passes through the point (-5, 7), and is perpendicular to line l1. If line l2 represents the graph of y=mx + b, then find m+b.

 Nov 12, 2020
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Line 1l represents the graph of 3x+4y = -14. Line l2 passes through the point (-5, 7), and is perpendicular to line l1. If line l2 represents the graph of y=mx + b, then find m+b.

 

Hello Guest!

 

Linie l1:

\(3x + 4y = -14\\ \color{blue}y=-\frac{3}{4}x-\frac{7}{2}\\ m_1=-\frac{3}{4}\)

 

Linie l2:

\(m_2=-\frac{1}{-\frac{3}{4}}\\ \color{blue}m_2=\frac{4}{3}\\ \color{BrickRed}P(-5,7)\\ y=m(x-x_P)+y_P\\ y=\frac{4}{3}(x+5)+7\)

\(y=\frac{4}{3}x+\frac{20}{3}+7\)

\(y=\frac{4}{3}x+13\frac{2}{3}\)

\(m+b=\frac{4}{3}+13\frac{2}{3}\)

\(m+b=15\)

laugh  !

 Nov 12, 2020

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