+0

help

0
113
1

Line 1l represents the graph of 3x+4y = -14. Line l2 passes through the point (-5, 7), and is perpendicular to line l1. If line l2 represents the graph of y=mx + b, then find m+b.

Nov 12, 2020

#1
+11086
+1

Line 1l represents the graph of 3x+4y = -14. Line l2 passes through the point (-5, 7), and is perpendicular to line l1. If line l2 represents the graph of y=mx + b, then find m+b.

Hello Guest!

Linie l1:

$$3x + 4y = -14\\ \color{blue}y=-\frac{3}{4}x-\frac{7}{2}\\ m_1=-\frac{3}{4}$$

Linie l2:

$$m_2=-\frac{1}{-\frac{3}{4}}\\ \color{blue}m_2=\frac{4}{3}\\ \color{BrickRed}P(-5,7)\\ y=m(x-x_P)+y_P\\ y=\frac{4}{3}(x+5)+7$$

$$y=\frac{4}{3}x+\frac{20}{3}+7$$

$$y=\frac{4}{3}x+13\frac{2}{3}$$

$$m+b=\frac{4}{3}+13\frac{2}{3}$$

$$m+b=15$$

!

Nov 12, 2020