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Let x1,x2,,x101 be positive real numbers such that x21+x22++x2101=1. Find the maximum value of x1x2+x1x3++x1x101.

 

 Mar 8, 2019
 #1
avatar+9675 
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Maximum occurs at x1=x2=x3==x101=1101.

Maximum value is 100(1101)2=100101.

 

Notes: The equation x21+x22++x2101=1 represents a 101-sphere with radius 1.

 

:)

 Mar 9, 2019
 #2
avatar+6252 
+1

I believe your answer but prove it.

Rom  Mar 9, 2019

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