Let x1,x2,…,x101 be positive real numbers such that x21+x22+⋯+x2101=1. Find the maximum value of x1x2+x1x3+⋯+x1x101.
Maximum occurs at x1=x2=x3=⋯=x101=1√101.
Maximum value is 100(1√101)2=100101.
Notes: The equation x21+x22+⋯+x2101=1 represents a 101-sphere with radius 1.
:)
I believe your answer but prove it.