The ratio of the age of a father and his son two years ago was 10:1. In five years, the age of the father will be 4 times the age of his son. what is the difference in the age of the father and son?
Let f be the age of the father and s be the age of the son.
The ratio of the age of the father to the age of the son 2 years ago was 10:1
The ratio of f - 2 to s - 2 = 10:1
f - 2 : s - 2 = 10:1
(f - 2) / (s - 2) = 10/1
(f - 2) / (s - 2) = 10
f - 2 = 10(s - 2)
f - 2 = 10s - 20
f = 10s - 18
In 5 years, the age of the father will be 4 times the age of the son.
f + 5 = 4(s + 5)
f + 5 = 4s + 20
f = 4s + 15
Now since f = 10s -18 and f = 4s + 15 we can say...
10s - 18 = 4s + 15
10s - 4s = 15 + 18
6s = 33
s = 5.5
Now we can find the value of f using this value of s
f = 4s + 15 = 4(5.5) + 15 = 37
the difference in the age of the father and son = f - s = 37 - 5.5 = 31.5
Let f be the age of the father and s be the age of the son.
The ratio of the age of the father to the age of the son 2 years ago was 10:1
The ratio of f - 2 to s - 2 = 10:1
f - 2 : s - 2 = 10:1
(f - 2) / (s - 2) = 10/1
(f - 2) / (s - 2) = 10
f - 2 = 10(s - 2)
f - 2 = 10s - 20
f = 10s - 18
In 5 years, the age of the father will be 4 times the age of the son.
f + 5 = 4(s + 5)
f + 5 = 4s + 20
f = 4s + 15
Now since f = 10s -18 and f = 4s + 15 we can say...
10s - 18 = 4s + 15
10s - 4s = 15 + 18
6s = 33
s = 5.5
Now we can find the value of f using this value of s
f = 4s + 15 = 4(5.5) + 15 = 37
the difference in the age of the father and son = f - s = 37 - 5.5 = 31.5