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Compute (1^2 + 2^2 + 3^2 + ... + 10^2)/770.

 Jul 5, 2020
 #1
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sumfor(n, 1, 10, (n^2))=462 / 770 =3 / 5 

 Jul 5, 2020
 #2
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Compute (1^2 + 2^2 + 3^2 + ... + 10^2)/770.

 

In general

 

Σnk=1k2=n(n+1)(2n+1)6

 

When n = 10 we have: 

Σ10k=1k2=10.11.216=385

 

And 385/770 = 1/2

 Jul 6, 2020

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