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3
avatar+192 

The perpendicular bisector 

 Nov 3, 2019
edited by tomsun  Nov 8, 2019

Best Answer 

 #3
avatar+19963 
0

Slope of the original line is   2-4  / 1-7 =  1/3

 

y = mx + b     

2 = 1/3 (1) + b   b= 5/3

original line is     y = 1/3 x + 5/3      perpindicular slope is   -3

Midpoint of original line is 4, 3

 

New line    3 = -3(4) + b    b = 15

 

New perpindicular line    y = -3x + 15 

 

 

Here is a graph:

https://www.desmos.com/calculator/nljlb5kiy8

 Nov 3, 2019
edited by ElectricPavlov  Nov 3, 2019
 #1
avatar+192 
0

Anyone?

 Nov 3, 2019
 #2
avatar
0

I'm getting y = 5x - 7.

 Nov 3, 2019
 #3
avatar+19963 
0
Best Answer

Slope of the original line is   2-4  / 1-7 =  1/3

 

y = mx + b     

2 = 1/3 (1) + b   b= 5/3

original line is     y = 1/3 x + 5/3      perpindicular slope is   -3

Midpoint of original line is 4, 3

 

New line    3 = -3(4) + b    b = 15

 

New perpindicular line    y = -3x + 15 

 

 

Here is a graph:

https://www.desmos.com/calculator/nljlb5kiy8

ElectricPavlov Nov 3, 2019
edited by ElectricPavlov  Nov 3, 2019

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