Let p and q be the two distinct solutions to the equation x^2 - 2x - 3 = 0. What is (p+1)(p+1)?
x^2 - 2x - 3 = 0
( x - 3) ( x + 1) = 0
Setting each factor to 0 and solving for x we get x = 3 and x = -1
If p = -1 then ( -1 + 1) ( -1 + 1) = (0) * (0) = 0
If p = 3 then ( 3 + 1) (3 + 1) = (4) * (4) = 16
Tysm!
