Given points $P(-2,7)$ and $Q(4,y)$ in a coordinate plane, for what value of $y$ is the slope of the line through $P$ and $Q$ equal to $\frac{-3}{2}$?

Guest Dec 3, 2017

#1**+1 **

Slope = rise/run = y1-y2 / x1-x2

-3/2 = (y-7) / (4-(-2))

-3/2 = (y-7) / 6

6 (-3/2) = y-7

-9 = y-7

y= -2

ElectricPavlov
Dec 3, 2017

#1**+1 **

Best Answer

Slope = rise/run = y1-y2 / x1-x2

-3/2 = (y-7) / (4-(-2))

-3/2 = (y-7) / 6

6 (-3/2) = y-7

-9 = y-7

y= -2

ElectricPavlov
Dec 3, 2017