Given points $P(-2,7)$ and $Q(4,y)$ in a coordinate plane, for what value of $y$ is the slope of the line through $P$ and $Q$ equal to $\frac{-3}{2}$?
Slope = rise/run = y1-y2 / x1-x2
-3/2 = (y-7) / (4-(-2))
-3/2 = (y-7) / 6
6 (-3/2) = y-7
-9 = y-7
y= -2
Slope = rise/run = y1-y2 / x1-x2
-3/2 = (y-7) / (4-(-2))
-3/2 = (y-7) / 6
6 (-3/2) = y-7
-9 = y-7
y= -2