+0

# help

0
63
1

How many integers n are there such that $$\dfrac{15 - n}{3 - n}$$ is also an integer?

May 24, 2020

#1
+25451
+1

How many integers $$n$$ are there such that $$\dfrac{15 - n}{3 - n}$$ is also an integer?

$$\begin{array}{|rcll|} \hline \dfrac{15 - n}{3 - n} &=& \dfrac{12+3-n}{3 - n} \\\\ &=& \dfrac{12}{3 - n}+\dfrac{3-n}{3 - n} \\\\ \mathbf{\dfrac{15 - n}{3 - n}} &=& \mathbf{\dfrac{12}{3 - n}+1} \\ \hline \end{array}$$

Divisors of 12:
1 | 2 | 3 | 4 | 6 | 12   (6 divisors)

$$\begin{array}{|rcll|} \hline 3-n &=& 1 \qquad \text{or} \qquad \mathbf{n=2} \\ 3-n &=& 2 \qquad \text{or} \qquad \mathbf{n=1} \\ 3-n &=& 3 \qquad \text{or} \qquad \mathbf{n=0} \\ 3-n &=& 4 \qquad \text{or} \qquad \mathbf{n=-1} \\ 3-n &=& 6 \qquad \text{or} \qquad \mathbf{n=-3} \\ 3-n &=& 12 \qquad \text{or} \qquad \mathbf{n=-9} \\ \hline \end{array}$$

$$n=\{2,1,0,-1,-3,-9\}$$

May 25, 2020