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Help.

 Jan 11, 2018
 #1
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3x^2 - 4 =  -x^4         add x^4 to both sides

 

x^4 + 3x^2  - 4  = 0     factor as

 

(x^2 + 4) (x^2 - 1)  = 0

 

(x^2 + 4)  (x + 1)  ( x-1)  = 0

 

Setting the last two factors to 0 and solving for x produces   x = -1 and x  = 1

 

Settting the first factor to 0, we have

 

x^2 +4  = 0   subtract 4 from both sides

 

x^2  =   -4         take both roots

 

x = ±√-4    =  ±2i

 

So the solutions are    1, -1, 2i, 2i

 

 

(s + 4v)^5  =

 

s^5  +  5(s^4)(4v) + 10(s^3)(4v)^2  + 10(s^2)(4v)^3  + 5(s)(4v)^4  + (4v)^5  

 

s^5  +  20s^4v  + 160s^3v^2   + 640s^2v^3  + 1280sv^4  +  1024v^5  [third answer ]

 

 

cool cool cool

 Jan 11, 2018

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