Two mechanics worked on a car. The first mechanic worked for 20 hours, and the second mechanic worked for 5 hours. Together they charged a total of 2375. What was the rate charged per hour by each mechanic if the sum of the two rates was 160 per hour?
Let the hourly rate of the first mechnic =F
Let the hourly rate of the second mechanic=S
F + S = 160.........................(1)
20F + 5S =2,375..................(2), solve for F, S
Use substitution or elimination to get:
F =$105 - hourly rate of the first mechanic.
S =$55 - hourly rate of the second mechanic.
