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A right cone has a base with a circumference of 16π inches and a height of 30 inches. The
height of this cone is reduced while the circumference stays the same. The volume of the shorter cone is 192π
cubic inches. What is the ratio of the shorter height to the original height? Express your answer as a common
fraction.

 Jan 6, 2021
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circumferance= pi*diameter, so the radius is 8, 8*8=64, 64pi is the area for base, 192pi/64pi=3, and 3*3=9, the ratio of the heights are 9/30, which is 3/10. If you're confused just search up how to calculate the column of a cone. Hope this helped.

 Jan 6, 2021

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