\(V=\dfrac 4 3 \pi r^3\\ \dfrac{dV}{dr} = 4 \pi r^2\\ \text{ok a bit of magic here}\\ dV = 4\pi r^2 dr\\ \dfrac{dV}{dt} = 4\pi r^2 \dfrac{dr}{dt} \\ 2 = 4 \pi (3)^2 \dfrac{dr}{dt}\\ \dfrac{dr}{dt} = \dfrac{1}{18\pi}~in/hr\)
Hi Guest,
You should not delete your question, because other people may have that question as well.
- Daisy
nnnnnn? Why did you delete your question? Other people may have the same or similar questions.