How many positive integers $n$ satisfy $\lfloor \sqrt{n} \rfloor = 5$?
\( \lfloor \sqrt{n} \rfloor = 5 \)
Note that
36 = 6^2
So
floor √35 = 5
And note that
25 = 5^2
floor √25 = 5
So....the number of positive integers, n, that satisfy this = 35 - 25 + 1 = 11
+980 
