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tan2x=? sin x=0,6 cos x= 0.8

 Sep 27, 2015
 #1
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tan2x = sin2x /cos2x =  [2sinxcosx]/[cos^2x - sin^2x]  = [2(.6)(.8)] / [ (.8)^2 -(.6)^2]  = 2[.48]/[.28] = .96/.28 = .48/.14 = .24/.7 = 24/7

 

 

 

cool cool cool

 Sep 27, 2015

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