The graph of $y=ax^2+bx+c$ passes through points $(0,5)$, $(1,10)$, and $(2,19)$. Find $a+b+c$.
thanks in advance
y = ax2 + bx + c
Since the graph passes through (1, 10) we know that when x = 1 , y = 10 .
So we can replace x with 1 and y with 10 .
10 = a(1)2 + b(1) + c
10 = a + b + c
a + b + c = 10
