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The graph of $y=ax^2+bx+c$ passes through points $(0,5)$, $(1,10)$, and $(2,19)$. Find $a+b+c$.

thanks in advance

 Jun 17, 2018
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y  =  ax2 + bx + c

 

Since the graph passes through  (1, 10)  we know that when  x = 1 ,  y = 10 .

 

So we can replace  x  with  1  and  y  with  10  .

 

y  =  ax2 + bx + c

 

10  =  a(1)2 + b(1) + c

 

10  =  a + b + c

 

a + b + c  =  10   smiley

 Jun 17, 2018

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