3 hunters have probabilities 2/5, 1/2 and 3/4 of hiting a target. Find the Probability that:
(a) All hits the Target
(b) Hits the Target
(c). None hits the Target
(c) One hits the Target
+128407 (a) All hit the target = (2/5)(1/2) (3/4) = 6 / 40 = 3/20
(b) ????
(c) None hit the target = (3/5)(1/2)(1/4) = 3 / 40
(d) P(one hits the target) =
P(first hits the target and other two miss) = (2/5)( 1/2) (1/4) = 2/40
P(second hits the target and first and third miss) = (3/5) (1/2) (1/4) = 3/40
P(third hits the target and first two miss) = (2/5)(1/2)(3/4) = 6/40
So P (one hits the target ) = 2/40 + 3/40 + 6/40 = 11 / 40
