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 3 hunters have probabilities 2/5, 1/2 and 3/4 of hiting a target. Find the Probability that:
(a) All hits the Target
(b) Hits the Target
(c). None hits the Target
(c) One hits the Target

 Mar 5, 2020
 #1
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(a)  All hit  the  target =  (2/5)(1/2) (3/4)  = 6 / 40  =  3/20

 

(b)   ????

 

(c)  None hit  the target  =  (3/5)(1/2)(1/4)  =  3 / 40

 

(d)  P(one hits  the  target)  = 

P(first hits  the target  and other two miss)  = (2/5)(  1/2) (1/4)  = 2/40

P(second  hits  the target and first and third miss)  = (3/5) (1/2) (1/4)  = 3/40

P(third hits  the target and first two miss)  = (2/5)(1/2)(3/4)  =  6/40

 

So  P (one  hits the target  )  =  2/40 + 3/40 + 6/40  =  11 / 40

 

 

cool cool cool

 Mar 5, 2020

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