Help!

To find the missing digits, we can use the fact that the total number of textbooks is 99.

We know that the total cost is a482.7b, where a and b are the missing digits. We also know that the total cost is equal to the price per textbook multiplied by the number of textbooks.

Since there are 99 textbooks, the total cost must be a multiple of 99. We can check the multiples of 99 until we find one that matches the given pattern:

99 * 1 = 99

99 * 2 = 198

99 * 3 = 297

99 * 4 = 396

99 * 5 = 495

99 * 6 = 594

99 * 7 = 693

99 * 8 = 792

99 * 9 = 891

99 * 10 = 990

From this list, we can see that the only multiple of 99 that matches the given pattern is 495. Therefore, the missing digits are a = 4 and b = 5.

Therefore, the total cost of the textbooks is $4482.75.

A school orders  textbooks, all for the same price. When the bill for the total order comes, the first and last digits are obscured. What are the missing digits?  a482.7b     

The other problem like this says that the school orders 99 textbooks.     

This problem has a blank spot where that 99 is in the other problem.     

So, I will assume the number of books in this problem should be 99.    

Consider that the price per book is multiplied by 99.   

And, multiplying by 99 incorporates multiplying by 9.    

The digits of the product of a number multiplied by 9    

will always sum to a total that is evenly divisible by 9.    

4 + 8 + 2 + 7 = 21 so the sum of the two missing     

numbers will have to add 6 (to make 27, which is     

evenly divisible by 9) or 15 (to make 36) to the 21.     

I found that 4482.72 is evenly divided by 99.   

So the missing numbers are a = 4 and b = 2.    

And the cost of each textbook was 45.28.    

_.   

The total cost of the textbooks is the number of textbooks multiplied by the price per textbook.

Since the number of textbooks is 99, which is an odd number, the last digit of the total cost must be odd.

We know that the last digit is either 1, 3, 5, 7, or 9.

We also know that the first digit is either 8, 9, or 1.

Since the first digit is 8 or 9, the total cost must be greater than or equal to 8000.

If the last digit is 1, then the total cost must be greater than or equal to 8001.

However, if the last digit is 9, then the total cost must be less than or equal to 8999.

Therefore, the last digit of the total cost must be 3, 5, or 7.

If the last digit is 3, then the total cost must be greater than or equal to 8003.

However, if the last digit is 7, then the total cost must be less than or equal to 8997.

Therefore, the last digit of the total cost must be 5.

If the last digit is 5, then the total cost must be greater than or equal to 8005.

However, if the first digit is 9, then the total cost must be less than or equal to 9995.

Therefore, the first digit of the total cost must be 8.

Therefore, the missing digits are 8 and 5.

The total cost of the textbooks is 8482.75.

The total price of the order is the number of textbooks ordered multiplied by the price of each textbook.

Since the number of textbooks ordered is 99, the total price of the order is a multiple of 99.

The number 99 is divisible by 9, so the total price of the order must also be divisible by 9.

The sum of the digits of a number that is divisible by 9 is also divisible by 9.

Therefore, the sum of the digits of the total price of the order must be divisible by 9.

The sum of the known digits of the total price of the order is 4 + 8 + 2 + 7 = 21.

Therefore, the sum of the missing digits must be 6, since 21 + 6 = 27, which is divisible by 9.

There are two possible pairs of digits that have a sum of 6: 0 and 6, and 1 and 5.

However, the first digit cannot be 0, so the missing digits must be 1 and 5.

Therefore, the total price of the order is $1482.75.

The answer is a = 8 and b = 1.