\(87= 21^x\\ ln87= ln21^x\\ ln87=x ln21\\ x=\frac{ln87}{ln21}\)
x= ln(87)/ln(21) = approx 1.4668665480402957
Melody, is there a reason you used natural log? I used log10 and got the same answer.
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Hi Guest,
No there is no reason, you can use any log you want.
Log 10 is an equally good alternative.