Hi there! I have figured out the answer but dont really know how to put it into words...
lets try though!
So we know that \(|x-3|\) will have to be positive because of the absolute value.
and if we expand out the radical \(\sqrt{x^2-9}\) we get\(\sqrt{(x-3)(x+3)}\)
Now that we have this we can subtract \(|x-3| \) from the left side. This means that our new equation is
\(\sqrt{(x-3)(x+3)}=-|x-3|\)
note: because of the absloute value we can get rid of the negitive
Because there is a radical we can square both sides to get
\((x-3)(x+3)=|x-3|^2\)
We have to disbtrube the left side so
\(x^2+3^2=(x-3)^2\)
simpify \(3^2=9\) you can solve from there!
also this might not be the best way to solve a question like this because it is my personal way aswell the way I learned it.
Hope this helps
~Wolf :D
+36916 Hmmmm..... I am not sure this is possible....
sqr (x^2-9) will always be positive which would mean |x-3| must be NEGATIVE for the terms to ADD to 0......absolute values cannot be negative..... Did you enter your question correctly?
