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how do i isolate x in y=b∗x^a?

 Jan 19, 2016

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 #1
avatar+26387 
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how do i isolate x in y=b∗x^a?

 

\(\begin{array}{rcll} y &=& b\cdot x^a \qquad & | \qquad :b\\ \frac{y}{b} &=& x^a \qquad & | \qquad 1^{\frac{1}{a}}\\ \left( \frac{y}{b} \right)^{\frac{1}{a}} &=& x^{ a\cdot \frac{1}{a} } \\ \left( \frac{y}{b} \right)^{\frac{1}{a}} &=& x^{\frac{a}{a} } \\ \left( \frac{y}{b} \right)^{\frac{1}{a}} &=& x^{1 } \\ \left( \frac{y}{b} \right)^{\frac{1}{a}} &=& x \\ \end{array}\)

 

laugh

 Jan 19, 2016
 #1
avatar+26387 
+10
Best Answer

how do i isolate x in y=b∗x^a?

 

\(\begin{array}{rcll} y &=& b\cdot x^a \qquad & | \qquad :b\\ \frac{y}{b} &=& x^a \qquad & | \qquad 1^{\frac{1}{a}}\\ \left( \frac{y}{b} \right)^{\frac{1}{a}} &=& x^{ a\cdot \frac{1}{a} } \\ \left( \frac{y}{b} \right)^{\frac{1}{a}} &=& x^{\frac{a}{a} } \\ \left( \frac{y}{b} \right)^{\frac{1}{a}} &=& x^{1 } \\ \left( \frac{y}{b} \right)^{\frac{1}{a}} &=& x \\ \end{array}\)

 

laugh

heureka Jan 19, 2016

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