At the MP Donut Hole Factory, Niraek, Theo, and Akshaj are coating spherical donut holes in powdered sugar. Niraek's donut holes have radius 6 mm, Theo's donut holes have radius 8 mm, and Akshaj's donut holes have radius 10 mm. All three workers coat the surface of the donut holes at the same rate and start at the same time. Assuming that the powdered sugar coating has negligible thickness and is distributed equally on all donut holes, how many donut holes will Niraek have covered by the first time all three workers finish their current donut hole at the same time?
surface area of sphere = 4 pi r^2
4 pi 3^2 4 pi 8^2 4 pi 10^2 divide all by 4pi
3^2 8^2 10^2
9 64 100 LCM is 14400
14400/9 = 1600 holes by Niraek
It should be 4 pi 6^2 then later 14400/36 = 400
And can you explain why do you get the LCM of those three numbers?
Ooops....see Hecticar's answer below....I used the wrong numbers...it should be
6^2 8^2 10^2
36 64 100 LCM 14400
14400/36 = 400