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At the MP Donut Hole Factory, Niraek, Theo, and Akshaj are coating spherical donut holes in powdered sugar. Niraek's donut holes have radius 6 mm, Theo's donut holes have radius 8 mm, and Akshaj's donut holes have radius 10 mm. All three workers coat the surface of the donut holes at the same rate and start at the same time. Assuming that the powdered sugar coating has negligible thickness and is distributed equally on all donut holes, how many donut holes will Niraek have covered by the first time all three workers finish their current donut hole at the same time?

 Jul 29, 2019
 #1
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+1

surface area of sphere = 4 pi r^2

 

4 pi 3^2       4 pi 8^2    4 pi 10^2     divide all by 4pi

3^2                    8^2            10^2

9                       64               100           LCM is 14400

 

14400/9 = 1600 holes    by Niraek

 Jul 29, 2019
 #2
avatar+8725 
+4

It should be  4 pi 6^2    then later    14400/36  =  400

 

And can you explain why do you get the LCM of those three numbers?

hectictar  Jul 29, 2019
 #3
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+2

Ooops....see Hecticar's answer below....I used the wrong numbers...it should be

 

6^2    8^2   10^2

36     64     100     LCM 14400

 

14400/36 = 400

Guest Jul 29, 2019
 #4
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+1

LCM, so they are all finishing a donut hole at the same time...ie synchronized.

Guest Jul 29, 2019

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