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If the two roots of the quadratic 4x^2+7x+k$ are $\frac{-7\pm i\sqrt{15}}{8}$, what is $k$?

 May 22, 2019
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\(\frac{-7\pm i\sqrt{15}}{8} \)

 

4x^2 + 7x + k

 

The product  of the  roots  =   k/4

 

So  

 

-7 + i √15               - 7  -  i √15

________    *      ___________    =

      8                           8

 

 

49  - i^2 (15)             49  +  15            64            

__________   =       ________  =   _____ =      1

       64                         64                  64            

 

So

 

1  = k/4

 

k =  4       

 

 

cool cool cool

 May 22, 2019

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