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How many values of \(x\) with \(0^\circ \le x < 990^\circ\) satisfy \(\sin x = -0.31\)?

 Jun 14, 2019
 #1
avatar+12212 
+1

990 : 18 = 55

 Jun 14, 2019
 #2
avatar+8962 
+1

990° / 180°  =  5.5

 

So there are only  5  values of  x  within  0° ≤ x < 990°  that satisfy  sin x  =  -0.31

 

They are:

 

x  ≈  198.059°

 

x  ≈  341.941°

 

x  ≈  558.059°

 

x  ≈  701.941°

 

x  ≈  918.059°

 Jun 14, 2019
edited by hectictar  Jun 14, 2019

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