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Suppose (x,4) is a point on the line that passes through the point (-3,0) with slope 1/2. Find x.

 Dec 4, 2018
 #1
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\(slope = \dfrac{y_2-y_1}{x_2-x_1} = \\ \dfrac{4-0}{x-(-3)} = \dfrac 1 2\\ \dfrac{4}{x+3}=\dfrac 1 2\\ 8 = x+3\\ x = 5\)

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 Dec 4, 2018
 #2
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Thanks Rom!

MobiusLoops  Dec 11, 2018

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