Write an equation in point-slope form for the line that has a slope of 9/8 and contains the point (9,−5).
+680 If you are familiar with the standard form it is \(y=ax+b\) where \(a\) is slope and \(b\) is a constant. Let's put our slope in to change the equation to: \(y=\frac{9}{8}x+b\). Now all we have to do is solve for \(b\) since we are given the point (9,-5). Let's plug it in to form the equation: \(-5=\frac{9}{8}\times9+b\). Now we solve it: \(-5=\frac{81}{8}+b\). So \(b\) is equal to \(-5-\frac{81}{8}\Rightarrow\frac{-121}{8}\). Now we rewrite the equation: \(y=\frac{9}{8}x-\frac{121}{8}\)
