The complex numbers \(a\) and \(b \) satisfy \(a \overline{b} = -1 + 5i.\)Find \(\overline{a} b.\)
Let a = m + ni
Let b conjugate = p - qi
So
a* (b conjugate) = (m + ni) (p - qi) = mp + (np - mq)i + nq = (mp + nq) + (np - mq) i = -1 + 5i
mp + nq = -1
np - mq = 5
And
a conjugate = m - ni
b = p + qi
So
(a conjugate) * b = ( m - ni) ( p + qi) = mp + (mq - np)i + nq = ( mp + nq) + (mq - np)i
So
(mp + nq) = -1
(mq - np) = -5
So
(a conjugate) * b = -1 - 5i
The complex numbers a and b satisfy \(a\overline{b} = -1 + 5i\).
Find \(\overline{a} b\).
\(\begin{array}{|rcll|} \hline a\overline{b} &=& -1 + 5i \\ \overline{a\overline{b}} &=& \overline{-1 + 5i} \quad | \quad \overline{a\overline{b}} = \overline{a}\overline{\overline{b}} \\ \overline{a}\overline{\overline{b}} &=& \overline{-1 + 5i} \quad | \quad \overline{a}\overline{\overline{b}} = \overline{a} b \\ \overline{a} b &=& \overline{-1 + 5i} \quad | \quad \overline{-1 + 5i} = -1 - 5i \\ \mathbf{\overline{a} b} &=& \mathbf{ -1 - 5i } \\ \hline \end{array}\)