If \(a+b=8, b+c=-3, \)and \(a+c=-5,\) what is th value of the product \(abc?\)
a + b = 8
b + c = -3
a + c = -5
Subtract the second equation from the first and we have that
a - c = 11 add this to the third equation and we get that
2a = 6
a = 3
3 + b = 8
b = 5
3 + c = -5
c = - 8
So abc = (3) (5)(-8) = - 120
