If \(a+b=8, b+c=-3, \)and \(a+c=-5,\) what is th value of the product \(abc?\)

a + b = 8

b + c = -3

a + c = -5

Subtract the second equation from the first and we have that

a - c = 11 add this to the third equation and we get that

2a = 6

a = 3

3 + b = 8

b = 5

3 + c = -5

c = - 8

So abc = (3) (5)(-8) = - 120