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If \(a+b=8, b+c=-3, \)and \(a+c=-5,\) what is th value of the product \(abc?\)

 Jan 10, 2019
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a + b =  8

b + c  = -3

a + c = -5

 

Subtract the second equation from the first  and we have that

 

 a - c =  11      add this to the third equation  and we get that

 

2a = 6

a = 3

 

a + b = 8

3 + b = 8

b = 5

 

a + c = -5

3  + c = -5

c =  - 8

 

So   abc  = (3) (5)(-8)   =  - 120

 

 

cool cool cool

 Jan 10, 2019

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