help

Question

0

604

1

AB is the diameter of a circle with radius 5. Q is on AB, and P is on the circle, so that PQ is perpendicular to AB. If AQ = 2, then find PB.

Guest May 31, 2020

Hephaestus · Answer 1 · 2020-05-31T05:06:03

$A_Q ={1\over5}AB$

$Arc[AP]= {1\over 5}Arc[AB]$

$PQ = { \sqrt{(P_O)^2-(AB)^2}}$

$PQ = 4$

$PB = {\sqrt{(PQ)^2+(QB)^2} }$

$PB =\sqrt{80}$

_R:

$PB = {4\sqrt{5}}$