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AB is the diameter of a circle with radius 5.  Q is on AB, and P is on the circle, so that PQ is perpendicular to AB.  If AQ = 2, then find PB.

 May 31, 2020
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\(A_Q ={1\over5}AB\)

\(Arc[AP]= {1\over 5}Arc[AB]\)

\(PQ = { \sqrt{(P_O)​​^2-(AB)​​^2}}\)

\(PQ = 4\)

\(PB = {\sqrt{​​(PQ)^2+(QB)^2} }\)

\(PB =\sqrt{80}\)

 

R:

\(PB = {4\sqrt{5}}\)

 May 31, 2020

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