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# help

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AB is the diameter of a circle with radius 5.  Q is on AB, and P is on the circle, so that PQ is perpendicular to AB.  If AQ = 2, then find PB.

May 31, 2020

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$$A_Q ={1\over5}AB$$

$$Arc[AP]= {1\over 5}Arc[AB]$$

$$PQ = { \sqrt{(P_O)​​^2-(AB)​​^2}}$$

$$PQ = 4$$

$$PB = {\sqrt{​​(PQ)^2+(QB)^2} }$$

$$PB =\sqrt{80}$$

R:

$$PB = {4\sqrt{5}}$$

May 31, 2020