The number of toy cars that Ray has is a multiple of 6. When he loses two of them, the number of cars that he has left is a multiple of n. If n is a positive even integer less than 10, then how many possible values are there for n?

Guest Aug 5, 2018

#1**+1 **

"*The number of toy cars that Ray has is a multiple of 6. When he loses two of them, the number of cars that he has left is a multiple of n. If n is a positive even integer less than 10, then how many possible values are there for n?"*

A multiple of 6 means the original number is divisible by both 2 and 3. Losing 2 means what is left is also divisible by 2, but not by 3. If it isn't divisible by 3 then it can't be divisible by 6. Hence n can only be 2, 4 or 8.

Alan Aug 5, 2018