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The number of toy cars that Ray has is a multiple of 6. When he loses two of them, the number of cars that he has left is a multiple of n. If n is a positive even integer less than 10, then how many possible values are there for n?

Guest Aug 5, 2018
 #1
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"The number of toy cars that Ray has is a multiple of 6. When he loses two of them, the number of cars that he has left is a multiple of n. If n is a positive even integer less than 10, then how many possible values are there for n?"

 

A multiple of 6 means the original number is divisible by both 2 and 3.  Losing 2 means what is left is also divisible by 2, but not by 3.  If it isn't divisible by 3 then it can't be divisible by 6.  Hence n can only be 2, 4 or 8.

Alan  Aug 5, 2018
 #2
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As Alan said if it is a multiple of 6 the has to be divisible by 2 and 3. now it is only divisible by 2. So only  2,4, or 8.

There are 3 possible values

wink

SVS2652  Aug 14, 2018

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