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Consider triangle ABC in the picture below. Angle A=30 degrees. Angle C=45 degrees. Side AB=10.

What are AC and BC?

 Jul 11, 2021
 #1
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Angle B = 105 degrees

 

Use law of sines       10 / sin 45   = AC / sin 105        solve for AC

                                 10 / sin 45 =  BC / sin 30          solve for BC

 Jul 11, 2021
 #2
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AC = 10(sin30) + 10(cos30)

 

BC = 10(sin45)        or      10(cos45) laugh

 Jul 13, 2021

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