Consider triangle ABC in the picture below. Angle A=30 degrees. Angle C=45 degrees. Side AB=10.
What are AC and BC?
Angle B = 105 degrees
Use law of sines 10 / sin 45 = AC / sin 105 solve for AC
10 / sin 45 = BC / sin 30 solve for BC
AC = 10(sin30) + 10(cos30)
BC = 10(sin45) or 10(cos45)
What are AC and BC?
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