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Find the equation of the line that passes through the points $(-2,1)$ and $(3,3)$.
Write your answer in the form $y=mx+b$ .

$\begin{array}{|rcll|} \hline \dfrac{y-1}{x-(-2)} &=& \dfrac{3-1}{3-(-2)} \\\\ \dfrac{y-1}{x+2} &=& \dfrac{2}{5} \\\\ y-1 &=& \dfrac{2}{5}(x+2) \\\\ y &=& \dfrac{2}{5}(x+2) + 1 \\\\ y &=& \dfrac{2}{5}x + \dfrac{4}{5} + 1 \\\\ \mathbf{y} &=& \mathbf{\dfrac{2}{5}x + \dfrac{9}{5}} \\ \hline \end{array}$