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In acute triangle \(ABC\), altitudes \(AD\)\(BE\), and \(CF\) intersect at the orthocenter \(H\). If \(BD=5\), \(CD=9\), and \(CE=42/5\), then find the length of \(HE\).

 
 Oct 14, 2021
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HE = 4.95

 
 Oct 14, 2021

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