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 \(fg(x)= \sqrt{{20-5x} \over x}\)

solve the equation fg(x) = 5 

 Aug 16, 2019
 #1
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\(\sqrt{\dfrac{20-5x}{x}}=5\\ \dfrac{20-5x}{x} = 25\\ 20-5x=25x\\ 20=30x\\ x=\dfrac 2 3\)

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 Aug 16, 2019

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