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4over5+square rot (x+0.2-5x x being 5

1.

\(\frac{4}{5}+\sqrt{x+0.2-5x}=5\)

\(\sqrt{x+0.2-5x}=\frac{21}{5}\)

\(x+0.2-5x=\frac{441}{25}\)

\(\)

\(-4x=\frac{441}{25}-0.2\)

\(x=\frac{\frac{441}{25}-0.2}{-4}\)

\(x=-4.36=4\frac{9}{25}\) 

2.

\(\frac{4}{5}+\sqrt{x+0.2-5x*x}=5\) 

\(\sqrt{x+0.2-5x*x}=\frac{21}{5}\) 

\(x+0.2-5x*x=\frac{441}{25}\)

\(-5x^2+x =\frac{441}{25}-0.2\)

\(-5x^2+1x -17.44=0\)

  a             b             c

\(\large x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

\(\large x = {-1 \pm \sqrt{1^2-348.8} \over -10}\)   the result is complex.

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