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A survey of 1108 employees at a software company finds that 621 employees take a bus to work and 445 employees take a train to work. Some employees take both a bus and a train and 321 employees take only a train. To the nearest percent find the probability that a randomly chosen employee takes a bus or a train to work.

 Feb 10, 2020
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445  employees take a train to work  and  321  take only a triain

 

So

 

445 -  321 =   124   take both a bus and train to work

 

So.....621 - 124  =  497  take only a bus 

 

So  the probability  that an employee  takes  a  bus or train (but not both)  =

 

[ 321  + 497 ]  /  1108   =

 

 

818 / 1108   ≈  .738  =   73.8%

 

 

cool cool cool

 Feb 10, 2020

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