[ 1 + sqrt(3) ]6
= 6C0·(1)6·(sqrt(3i))0
+ 6C1·(1)5·(sqrt(3i))1
+ 6C2·(1)4·(sqrt(3i))2
+ 6C3·(1)3·(sqrt(3i))3
+ 6C4·(1)2·(sqrt(3i))4
+ 6C5·(1)1·(sqrt(3i))5
+ 6C6·(1)0·(sqrt(3i))6
Easier way:
1^6=1
sqrt(3i)=-27i
The answer would be -27i+1
Hope this helped!