There are two positive numbers such that sum of twice the first and thrice the second is 39, while the sum of thrice the first and twice the second is 36. Find the larger number.
+36914 2a + 3b = 39 and
3a + 2b = 36 (this is given) multiply second equation by - 1.5 to get
-4.5 a - 3b = -54 add this to the first equation to get
-2.5 a = -15
a = 6 Now you should be able to find 'b' and determine which is larger.....
