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Solve 2^{2x} - 8 * 2^x + 12 = 0.

 Dec 3, 2019
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Solve 2^{2x} - 8 * 2^x + 12 = 0.

 

Hello guest!

 

\(2^{2x} - 8 * 2^x + 12 = 0. \\ u=2^x\\ u^2-8u+12=0\\ u=-\frac{p}{2}\pm\sqrt{(\frac{p}{2})^2-q}\\ u=4\pm\sqrt{16-12}\)

\(u_1=6\\ u_2=2\)

 

\(2^{x_1}=6\\ x_1\cdot ln2=ln6\\ x_1=\frac{ln6}{ln2}\)

\(x_1=2.5849625\)

 

\(2^{x_2}=2\\ 2^{x_2}=2^1 \)

\(x_2=1\)

laugh  !

 Dec 3, 2019

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