Solve for x:
(10-5 (x-2))/5 = (x+1)/10
-5 (x-2) = 10-5 x:
(10-5 x+10)/5 = (x+1)/10
Add like terms. 10+10 = 20:
(20-5 x)/5 = (x+1)/10
Multiply both sides by 10:
(10 (20-5 x))/5 = (10 (x+1))/10
10/5 = (5×2)/5 = 2:
2 (20-5 x) = (10 (x+1))/10
(10 (x+1))/10 = 10/10×(x+1) = x+1:
2 (20-5 x) = x+1
Expand out terms of the left hand side:
40-10 x = x+1
Subtract x from both sides:
40+(-10 x-x) = (x-x)+1
-10 x-x = -11 x:
-11 x+40 = (x-x)+1
x-x = 0:
40-11 x = 1
Subtract 40 from both sides:
(40-40)-11 x = 1-40
40-40 = 0:
-11 x = 1-40
1-40 = -39:
-11 x = -39
Divide both sides of -11 x = -39 by -11:
(-11 x)/(-11) = (-39)/(-11)
(-11)/(-11) = 1:
x = (-39)/(-11)
The sign of (-39)/(-11) is positive, so (-39)/(-11) = 1×39/11:
Answer: |x = 39/11
1/5[10-5(x-2)]=1/10(x+1) multiply both sides by 10
2[10-5(x-2)] = (x+1)
2[10 -5x +10] = x + 1 get rid of the inner bracket
20 - 10x +20 = x + 1 distibute 2 on the LHS.
-10x + 40 = x + 1 subtract x and 1 from both sides
-11x + 39 = 0 subtract 39 from both sides
-11x = - 39 divide both sides by -11
x = 39/11 =3 6/11
