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Thanks!

 Sep 29, 2019
 #1
avatar+655 
+1

So we already know that a triangle's angles sum up to 180 correct? 

So what you want to do is use the given angle 114 to find Angle ACD. 

What you do is do 180-114 and you get 66 which is the angles for ACB 

and then you do \(66+66+66-x=180\)

\(198-x=180\)

\(x= 18\)

 

\(66-18=48\)

 

\(\angle ACD = 48°\)

.
 Sep 29, 2019
 #2
avatar+655 
+1

correct me if i am wrong :')

Nirvana  Sep 29, 2019
 #3
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The answer is actually 18 Degrees since we have to find ACD, not DCB. Thanks for the answer though :)

 Sep 29, 2019
 #4
avatar+2417 
+2

Notice that triangle CDB is isoceles, with DB being the base. And ABC is isoceles.

 

I can assume you can use your knowledge on isoceles triangles and straight angles to figure out the answer. laugh

CalculatorUser  Sep 30, 2019
 #5
avatar+655 
+1

oh ripp :(

Nirvana  Sep 30, 2019

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