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Marie invested $12,000 in two different simple interest accounts. She invested part of the money at 8% and the rest at 6%. How much was invested at each amount, if the total interest earned was $872?

 Apr 4, 2020
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Assuming ONE year investment

 

x = 8% amount

12 000 - x = 6% amount

 

.08 (x)  + .06(12000-x) = 872        solve for 'x' the 8% amount     then 6% amount = 12000-x

 Apr 4, 2020

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