Marie invested $12,000 in two different simple interest accounts. She invested part of the money at 8% and the rest at 6%. How much was invested at each amount, if the total interest earned was $872?
+36916 Assuming ONE year investment
x = 8% amount
12 000 - x = 6% amount
.08 (x) + .06(12000-x) = 872 solve for 'x' the 8% amount then 6% amount = 12000-x
