help

For how many ordered pairs of positive integers (x,y)  does the equation  $\dfrac{1}{x} +\dfrac{2}{y}=\dfrac{1}{3}\\ $ hold?

$\dfrac{1}{x} +\dfrac{2}{y}=\dfrac{1}{3}\\ $

x=0 and y = zero are both asymptotes.

as x tends to infinity    y tends to 6

as y tends to infinity     x tends to 3

$\dfrac{1}{x} +\dfrac{2}{y}=\dfrac{1}{3}\\ \frac{2}{y}=\frac{1}{3}-\frac{1}{x}\\ \frac{2}{y}=\frac{x-3}{3x}\\ \frac{y}{2}=\frac{3x}{x-3}\\ y=\frac{6x}{x-3}\\ $

for y to be positive x>3

For x to be positive y>6

I found these points using  EXCEL.   I found 6 ordered pairs.