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avatar+160 

Thanks! 

 Apr 13, 2019
 #1
avatar+100571 
+1

Since ABCD is a unit square....its height = 1  an d its base = 1

So....its area = 1

And since EFGH  = 1/4 area of ABCD, then its base, FE, just must be 1/4

 

 

So.....that means that  BF + EA  = 3/4

So...the combined areas of BFGC  and EAHD must also be 3/4

But FGC  = 1/2 of BFGC   and EAH = 1/2 of EAHD

So...FGC + EAH  = (1/2) ( BFGC + EAHD)  = (1/2)(3/4) = 3/8

 

So...the area of quadilateral  AFCH  =

 

area of EFGH   + (area of FGC + area of EAH)   =

  

       (1/4 )          +      (3/8)        =

 

      (2/8)           +       (3/8)    =

 

 

                 5 / 8               

 

 

cool cool cool

 Apr 13, 2019
 #2
avatar+160 
+1

Thanks CPhill!

 Apr 14, 2019

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