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What is the general solution to the equation?

2√tanθ=2sinθtanθ

 Apr 10, 2020
 #1
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I'll use  x  instead of  theta....it won't matter....

 

2√tanx=2 sinx tanx     divide  both sides by 2

 

√tan x  =  sin x tan x      and we can write

 

sin x tan x  - √tan x  =   0    factor

 

√tan x  ( sinx - 1)  =  0

 

So either

 

√tan x  = 0      square  both sides

 

tan x  = 0       and  this  happens at  x  =   0 + n*pi

 

Or

 

sin x - 1  =  0

 

sin x  =  1

 

And  this happens at  x  = pi/2 + n * 2pi

 

Where  n is an integer

 

 

 

cool cool cool

 Apr 10, 2020

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