If $a$ is the $x$-intercept, $b$ is the $y$-intercept, and $m$ is the slope of the line with equation $\frac{x}4 + \frac{y}{12} = 1$, then what is the value of $a + b + m$?

\(\frac{x}4 + \frac{y}{12} = 1 \)

If x=0 y=12 so the y intercept b = 12

If y=0 x=4 so the x intercept a = 4

Thinking of the graph in my head I can see this has a negative gradient.

m= - rise / run = - 12/4 = -3

a+b+m = 4+12+ -3 = 13